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ioda
3 years ago
8

Yuto solved the equation below. What is the solution to Yuto’s equation?

Mathematics
2 answers:
pishuonlain [190]3 years ago
4 0

Answer: Yuto's equation has no solution.

Step-by-step explanation:

To find the solution  to Yuto’s equation, you need to solve for the variable "x":

Apply Distributive property:

-2(x+5)=-2(x-2)+5\\\\-2x-10=-2x+4+5\\\\-2x-10=-2x+9

Add 2x to both sides of  the equation:

-2x-10+2x=-2x+9+2x\\\\0x-10=9\\\\-10=9\ (False)

Therefore, the equation has no solution.

ValentinkaMS [17]3 years ago
3 0

For this case we have the following equation:

-2 (x + 5) = - 2 (x-2) +5

We apply distributive property to the terms within parentheses:

-2x-10 = -2x + 4 + 5

We add similar terms to the right side of the equation:

-2x-10 = -2x + 9

We add 2x to both sides of the equation:

-10 = 9

Equality is not fulfilled, so the equation has no solution.

Answer:

It has no solution

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Step-by-step explanation:

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Ben left a 20% tip on his bill at a restaurant. The bill was $40
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Step-by-step explanation:

Multiply 40 by 20% to find out how much money he gave for tip.

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Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)
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Answer:

point - slope form

 y - 1 = 3 (x-0)

Step-by-step explanation:

<u><em>step(i):-</em></u>

Given points are (0,1) and (2,7)

The slope of the line

     m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

    m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} } = \frac{7-1}{2-0} = \frac{6}{2}  = 3

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<u><em>Step(ii):-</em></u>

point -slope form

   y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

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2 years ago
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Read 2 more answers
OX and OY are two straight lines which intersect at an acute angle of 60°. OX = 4.5cm and OY = 5cm . The point M is on OX such t
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Therefore the point P is at 3.46 cm from O and it lies on the angle bisector of ∠XOY

<h3>What is an Angle Bisector ?</h3>

The ray that bisects the angle into half is called Angle Bisector.

It is given that ∠XOY = 60 degree

the length of OX = 4.5 cm

OY =5 cm

The point M is on OX such that

OM = 2 MX

so The M is at 3 cm from O

The point P lies in the acute angle such that the distance between point P and OX and OY is always same and at 3 cm from M

According to the angle bisector theorem converse states that if a point is in the interior of an angle and is at equal distance from the sides  then it lies on the bisector of that angle.

As it can be seen from the image that a point equidistant from the rays , at 3 cm from M will be at

By Pythagoras Theorem

3² +3² = OP²

OP = 2\sqrt{3} = 3.46 cm from O

To know more about Angle Bisector

brainly.com/question/12896755

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