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3 years ago

Select the correct answer from the drop-down menu.

Mathematics

1 answer:

jonny [76]3 years ago

7 0

Answer:

Answer is D (got it right on plato)

Step-by-step explanation:

There are 4 of each king and queen in each standard deck of 52 cards.

4+4=8

8/52=0.1538 or 15.38%

Twenty cards are chosen from a pack of cards at random

In A there are 0 kings and 1 queen

0+1= 1; 1/20=.05 or 5%

In B there are 2 kings and 4 queens

2+4=6; 6/20=0.3

In C there are 0 kings and queens

0/20=0

In D there are 2 kings and 1 queen

2+1= 3; 3/20=0.15 or 15%

D is your answer because it is the closest to the probability (0.1538 or 15.38%)

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A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write

REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0

2 years ago

Need help with this.

sweet [91]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Let t as y² + 5y .

${y}^{2} + 5y = t$

Rewrite the equation :

$t - \frac{36}{t} = 0 \\$

Multiply sides by t

$t \times (t - \frac{36}{t} ) = t \times 0 \\$

${t}^{2} - 36 = 0$

Add sides 36

${t}^{2} - 36 + 36 = 0 + 36$

${t}^{2} = 36$

$t = ± \: 6$

_________________________________

So :

${y}^{2} + 5y = 6$

Subtract sides 6

${y}^{2} + 5y - 6 = 6 - 6$

${y}^{2} + 5y - 6 = 0$

$(y + 6)(y - 1) = 0$

$y = - 6 \: \: or \: \: y = 1$

##############################

${y}^{2} +5y = - 6$

$No \: \: solution$

_________________________________

Thus (( y = 1 )) and (( y = - 6 )) are the roots of the equation .

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8 0

3 years ago

In the diagram shown, chords AB and CD intersect at E.

frez [133]

Check the picture below.

$4x~~ = ~~\cfrac{120~~ + ~~2x}{2}\implies 8x=120+2x\implies 6x=120 \implies x=\cfrac{120}{6} \\\\\\ x=20~\hfill \stackrel{\measuredangle 4x}{4(20)=80^o}~\hfill \underset{180~~ - ~~4x}{\stackrel{\measuredangle AED}{180^o-80^o=100^o}}$

7 0

1 year ago

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Lisa [10]

Answer:

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5 0

3 years ago

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maksim [4K]

Answer:

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Step-by-step explanation:

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3 years ago