Answer:
86
Step-by-step explanation:
First, we should use the rule of:
B: bracket
O: of
D: division
M: multiplication
A: addition
S: subtraction
so, before adding we should multiply
or;36+50
or;86 ans.
No, that's not true. The input variable of a sequence is called the index, which is a counter, such as 1, 2, 3, 4, ... Note that all of these counters are positive integers. Normallly I use index i = 1 to denote the first term of a sequence, i = 2 the second term, and so on.
Decimals and irrational numbers are completely unsuitable for serving as such counters.
Answer:
More than 50
Step-by-step explanation:
To solve, we need to first see that the function is h(n). Picking main points from the question statement:
- h(n) is the product of all even integers (From 2 to n)
- p is the smallest factor of h(100)+1
- h(100)+1 , here n=100
From here, we can write h(100) as:
h(100) =
h(100) = =
so,
h(100)+1 =
Now two numbers,
h(100) and h(100)+1 are consecutive integers and since they are consecutive so they are co-prime. Hence they only have common factor of 1. Example, 13 and 14 have only common factor of 1
As h(100) has all prime numbers from 1 to 50 and according to above statement h(100)+1 won't have any prime factor from 1 to 50, so the smallest prime factor p is greater than 50.