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sergiy2304 [10]

3 years ago

5

Between which pair of numbers is the exact product of 379 and 8

1 answer:

Masja [62]3 years ago

6 0

I am assuming this is multiple choice, but no answers were provided. If you multiply 379 by 8, you would get 3032.

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Slope=1÷5; y intercep = -5

sertanlavr [38]

The equation is
$y = \frac{1}{5} x - 5$

3 0

3 years ago

What fraction is equal to 9/36

Lemur [1.5K]

The answer is 1 / 4

hope this helps (:

8 0

3 years ago

Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below.

wlad13 [49]

We have to use the functions:
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7

6 0

3 years ago

You guysss pls help me

hichkok12 [17]

Answer:

option B) $\frac{1}{12}$

Step-by-step explanation:

According to the given conditions, the total number of outcomes are 24.

The probability that of drawing hearts card is

P= $\frac{(total number of hearts cases)}{(total number of cases)}$

total number of hearts cases= 6

thus P= $\frac{6}{24} = \frac{1}{4}$

now the probability of 4 or 6 is,

P= $\frac{(total number of 4 or 6 cases)}{(total number of cases)}$

thus P= $\frac{8}{24} = \frac{1}{3}$

thus, by multiplication law,

final probality is P= $(\frac{1}{4})(\frac{1}{3})$

P= $\frac{1}{12}$

5 0

3 years ago

A rectangle has a length of 15 centimeters and a width of 7 centimeters. What is the area of the rectangle?

Flura [38]

<h3><em><u>given</u></em><em><u>:</u></em></h3>

<em><u>length</u></em><em><u>=</u></em><em><u> </u></em><em><u>15cm</u></em>

<em><u>width</u></em><em><u>=</u></em><em><u> </u></em><em><u>7cm</u></em>

<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>

<em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>rectangle</u></em><em><u>.</u></em>

<h3><em><u>solution</u></em><em><u>:</u></em></h3>

<em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>rectangle</u></em><em><u>=</u></em><em><u> </u></em><em><u>length</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>width</u></em><em><u> </u></em>

<em><u>a</u></em><em><u>=</u></em><em><u> </u></em><em><u>l</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>w</u></em>

<em><u>a</u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>5</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>7</u></em>

<em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>5</u></em><em><u> </u></em><em><u>cm</u></em><em><u>^</u></em><em><u>2</u></em>

6 0

2 years ago

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