Answer:
<h3>
A = ²⁵/₄x² + ⁷⁵/₂x + 50</h3>
Step-by-step explanation:
L = ⁵/₂x + 10
W = ⁵/₂x + 5
A = L•W
A = (⁵/₂x + 10)(⁵/₂x + 5)
A = ⁵/₂x•⁵/₂x + ⁵/₂x•5 + 10•⁵/₂x + 10•5
A = ²⁵/₄x² + ²⁵/₂x + ⁵⁰/₂x + 50
A = ²⁵/₄x² + ⁷⁵/₂x + 50
Or if yoy mean:
L = 5/(2x) + 10
W = 5/(2x) + 5
A = [5/(2x) + 10][5/(2x) + 5] = 25/(4x²) + 75/(2x) + 50
C is the answer. By only looking at the domain (the stuff on the right in the functions), you can see that the first equation has a hole at x=2, meaning it does not have a value here at x=2. When x<2, there are values for the 1st function. When x>2, there are values for the second function, as well as when x=2
Answer:
132, 390, 244, 492
Step-by-step explanation:
those are the answers in order
Answer:
The diameter of the circle O is <em>12 units</em>
Step-by-step explanation:
There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of

and the triangle B0C is right
<u>Relations in the Circle</u>
The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.
Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r
Applying Pythagoras's theorem:

Thus we have




The diameter of the circle O is D=2(6) = 12 units