All categories

3 years ago

Which point is located at (0,-7)?

Mathematics

2 answers:

Flura [38]3 years ago

7 0

Answer:

Step-by-step explanation:

Scilla [17]3 years ago

3 0

E is the point located at (0,-7)

You might be interested in

To solve the equation 5sin(2x)=3cosx, you should rewrite it as___.

galina1969 [7]

Answer:

Step-by-step explanation:

We want to solve the equation:

$5\sin(2x)=3\cos(x)$

To do so, we can rewrite the equation.

Recall the double-angle for sine:

$\sin(2x)=2\sin(x)\cos(x)$

By substitution:

$5\left(2\sin(x)\cos(x)\right)=3\cos(x)$

Distribute:

$10\sin(x)\cos(x)=3\cos(x)$

We can subtract 3cos(x) from both sides:

$10\sin(x)\cos(x)-3\cos(x)=0$

And factor:

$\cos(x)\left(10\sin(x)-3\right)=0$

Hence, our answer is A.

*It is important to note that we should not divide both sides by cos(x) to acquire 10sin(x) = 3. This is because we need to find the values of x, and one or more may result in cos(x) = 0, and we cannot divide by 0. Hence, we should subtract and then factor.

5 0

2 years ago

Read 2 more answers

Given: A, B, and C What is the value of X in the matrix equation AX + B = C?

Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

$A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}$

$B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}$

$C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}$

AX + B = C

AX = C - B

C - B = $\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}$ = $\begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}$