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kati45 [8]
3 years ago
12

Somebody please help I need to know how to do this for a big test.

Mathematics
1 answer:
Valentin [98]3 years ago
4 0
No because 3 can go into 63 evenly and the denominator would be left the same.
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Function g can be thought of as a scaled version of f(x) = x^2 <br> write the equation for g(x)
dsp73

Answer:

g(x) = - x^2

Step-by-step explanation:

The negative sign flips the f(x) graph across the x-axis.

4 0
3 years ago
Please help me fast :) I'll give brainly and you'll get 15 points
Alekssandra [29.7K]

Answer:

Rational

Step-by-step explanation:

8 0
3 years ago
F(x) = -6x + 4<br> f (x) = 28
Eva8 [605]

Answer:

x = - 4

Step-by-step explanation:

Given f(x) = - 6x + 4 and f(x) = 28, then equating

- 6x + 4 = 28 ( subtract 4 from both sides )

- 6x = 24 ( divide both sides by - 6 )

x = - 4

4 0
3 years ago
You find 72 coins consisting only of nickels, dimes, and quarters, with a face value of $10.20. However, the coins all date from
Oliga [24]

Answer:

You have found 24 nickels.

Step-by-step explanation:

Let N be the number of nickles, D be the number of dimes and Q be the number of quarters. The number of coins and their face values are given by the following expressions, respectively:

N+D+Q=72\\0.05N+0.10D+0.25Q=10.20

As of now we have three variables and two expressions, the final expression needed to solve the linear system is given by the amount offered by the coin dealer:

10N+20D+15Q=1,060

Solving the linear system:

N+D+Q=72\\5N+10D+25Q=1,020\\10N+20D+15Q=1,060\\\\10N-10N+20D-20D+15Q-50Q=1,060-(2*1,020)\\-35Q=-980\\Q=28\\\\5N-10N+10D-10D+25Q-10Q=1,020-720\\-5N+15Q=300\\-5N=300-(15*28)\\N=24

You have found 24 nickels.

7 0
3 years ago
Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st
Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)  

b) n=523 rounded up to the nearest integer  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=530 represent the sample mean for the sample  

\mu population mean

s=70 represent the sample standard deviation  

n=48 represent the sample size (variable of interest)  

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that z_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

530-2.01\frac{70}{\sqrt{48}}=509.692  

530+2.01\frac{70}{\sqrt{48}}=550.308  

So on this case the 95% confidence interval would be given by (509.592;550.308)  

Part b

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (a)  

Assuming that \hat \sigma =s

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (b)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (b) we got:  

n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523  

So the answer for this case would be n=523 rounded up to the nearest integer  

3 0
3 years ago
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