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kati45 [8]
3 years ago
12

Somebody please help I need to know how to do this for a big test.

Mathematics
1 answer:
Valentin [98]3 years ago
4 0
No because 3 can go into 63 evenly and the denominator would be left the same.
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a circle is divided into 18 equal parts how many degrees is the angle for each part? how many degrees is the angle for 5 parts?
Ket [755]
There are 360 degrees in a circle, and we have 18 pieces, so we need to see how many times 18 goes into 360. We can find this out by dividing.

360/18=20

You can check this by multiplying 20 and 18 (it equals 360)!

So, each fraction of the circle will be 20 degrees.

If you take 5 of these 20 degree pieces, you'll need to multiply them by 20 to see how many degrees they'd be.

You need to multiply by 20 because each piece is 20 degrees, and we need to find how many degrees 5 pieces is. It's the same as doing
20+20+20+20+20! :)

20*5=100. 5 parts will be 100 degrees.


Hope I helped! :)
4 0
3 years ago
How many different orders can three students be selected from 10?
KATRIN_1 [288]
That would be the number of permutations of 3 from 10.

= 10P3  =  10! / 7! =  10*9*8 =  720
5 0
3 years ago
Math question please help urgently
djverab [1.8K]

Answer:

0, negative 9 and your welcome

6 0
3 years ago
At six am the temperature was -8°c at noon the temperature was 3°c what was the change in temperature between 6 am and noon
Roman55 [17]
The temperature change from 6am to noon is 11°c
4 0
3 years ago
Plz answer question in screen shot
liberstina [14]

Answer:

tan theta = 2 sqrt(5) /15

Step-by-step explanation:

sin theta = opp / hypotenuse

sin theta = 2/7

We can use the Pythagorean theorem to find the length of the adjacent side

a^2 + b^2 = c^2

2^2 +adj^2 = 7^2

4 + adj^2 = 49

adj ^2 = 49-4

adj^2 = 45

Taking the square root of each side

adj = sqrt(45) = sqrt(9*5) =sqrt(9) sqrt(5) = 3 sqrt(5)

The tan theta = opp/ adj

tan theta = 2 / 3 sqrt(5)

Multiply by sqrt(5) / sqrt(5)

                = 2 sqrt(5) / 3 *5

                 = 2 sqrt(5) /15

6 0
3 years ago
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