Vcylinder=hpir^2
Vsphere=(4/3)pir^3
Vcone=(1/3)hpir^2
Vcylinder=15*pi*5^2=375pi in^3
Vsphere=(4/3)*pi*6^3=288pi in^3
Vcone=(1/3)*15*pi*8^2=320pi in^3
greatest is Vcylinder at 375pi in^3
answer is A (cylinder)
Answer:
see explanation
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (- y, x ) , then
(3, 3 ) → (- 3, 3 )
(3, 4 ) → (- 4, 3 )
(5, 3 ) → (- 3, 5 )
U + 4/5 = 2 and 1/3
Subtract 4/5 from each side of the equation:
U = (2 and 1/3) - (4/5)
Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.
First let's change (2 and 1/3) to a fraction: 2 and 1/3 = 7/3
So you have to find the value of (7/3) - (4/5) .
In order to add or subtract fractions, they need to have a common denominator.
The least common multiple of 3 and 5 is 15, so that's a good choice.
7/3 = 35/15
4/5 = 12/15
Now the problem is: (35/15) - (12/15).
That's 23/15 . . . . . the same thing as <u>1 and 8/15</u> .
That's the value of ' U '. What an ugly number !
