Option C is correct because it is a trinomial with a leading coefficient of 3 and a constant term of -5
Step-by-step explanation:
We need to pick the expression that matches this description:
A trinomial with a leading coefficient of 3 and a constant term of -5
First lets explain the terms:
Trinomial: a polynomial having 3 terms
Leading coefficient: The constant value of variable having highest power
Constant term: Having no variable and value cannot be changed.
Now using these definitions, we can choose the correct option
Option A is incorrect because the expression has 2 terms
Option B is incorrect because it is a trinomial but the leading coefficient is -5 and not 3 constant term is 3 and not -5.
Option C is correct because it is a trinomial with a leading coefficient of 3 and a constant term of -5
Option D is incorrect because it is a trinomial but the leading coefficient is 3 but constant term is 1 and not -5.
So, Option C is correct.
Keywords: Algebra
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He would run a 1=dx jsnsissnsnjss
<u>Answer:</u>
both numbers are negative
negative number is greater than the positive number
<u>Step-by-step explanation:</u>
In order to add two rational numbers and get a negative value, one of two scenarios should occur:
<u>1- both numbers are negative.</u>
2- negative number is greater than the positive number
<span>△PQR is similar to △STU
</span>m∠R = m∠U = 96°
m∠Q = m∠T = 6
m∠P = 180 - ( 96 + 6)
m∠P = 180 - 102
m∠P = 78
answer
m∠P = 78
The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
