If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
1 answer:
Answer:
<h2>16kg</h2>Step-by-step explanation:
This problem is borers on elasticity of materials.
according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>
where F is the applied force in N
k is the spring constant N/m
e is the extension in meters
Given data
mass m= 24kg
extensnion=15cm in meters= =
we can solve for the spring constant k
we also know that the force F = mg
assuming
therefore
We can use this value of k to solve for the mass that will cause an extension of
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Answer:
(B) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 60.6 , 64.3 , 79.1 , 86.5
Step-by-step explanation:
The rate of change is found by using the formula for slope:
For option A, this gives us
m =(64.4-61.0)/(3-2) = 3.4/1 = 3.4
This is not more than relationship A.
For option B, we have
(64.3-60.6)/(3-2) = 3.7/1 = 3.7
This is more than relationship A.
For option C, we have
(65.3-61.8)/(3-2) = 3.5/1 = 3.5
This is not more than relationship A.
For option D, we have
(64.6-61.0)/(3-2) = 3.6/1 = 3.6
This is not more than relationship A.