Slope ~3
y intercept ~7
y= equation ~y=3x+7
That would be option A as the angles and sides ( the AS) have already been stated.
Furthest from 0, so I am going to take the absolute value of these numbers. The absolute value will tell us how far away from 0 these numbers are.
|-1/2| = |- 0.5| = 0.5
|8/9| = |0.88| = 0.88
|0.2| = 0.2
so the number furthest from 0 is 8/9
A. √(0.8^2) + (0.6^2) = √1 = 1 => OK
<span>b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK
c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle
d.(1,1)
= √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.</span>
