The given equations are

(1)

(2)
When t=0, obtain

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means

.
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means

.
Because

, obtain

Answer:
The slope of the curve at t=0 is 1/6.
Answer:
x=2 2/3
Step-by-step explanation:
The equation also means that x=8^3
8/3=2 2/3
Answer: 4 hours 31 min
Step-by-step explanation: first you need to simplify or solve 4/2 which is 2 because 4 divided by 2 is 2 and on Tuesday he spent 2 hours and 31 min no simply add 2 hours plus 2 hours and 31 min which gives you 4 hours and 31 min
Answer:
the height is 12
Step-by-step explanation:
you would take the area (108 mm2), divide that by the base (18 mm) and multiply it by 2
Answer:
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