Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
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Answer:
g^5h^2
Step-by-step explanation:
12g^5h^4, g^5h^2
This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
So far you see every single prime factor of each monomial.
Now I will mark the ones that are present in both. Those are the common factors.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
The greatest common factor is the product of all the factors that appear in both monomials.
GCF = g * g * g * g * g * h * h = g^5h^2
Answer:
Step-by-step explanation:
I don’t know
The second option - 3/25.
The probability of the first one is 3 blue socks over 10 socks in total = 3/10
The probability of the second one is 4 red socks over 10 socks in total = 4/10
Multiply the two probabilities to get the probability of having the first sock as blue and the second sock as red.
3/10 * 4/10 = 3/25
