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3 years ago

Choose all the answers that apply.

Chemistry

2 answers:

zalisa [80]3 years ago

7 0

Orbit around the nucleus and have a negative charge.

natta225 [31]3 years ago

3 0

The correct answers are the first and the second

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at 100c the vapour pressure of a solution of 6.5g of solute in 100g of water is 732mm if kb is 0.52 k/m the boiling point of sol

sergey [27]

Answer:101.105⁰c

Explanation:

8 0

3 years ago

Calculate the molarity of a MgSO4, solution

Gala2k [10]

Answer:

0.058M is molarity of the solution

Explanation:

Molarity is defined as the ratio between the moles of solute (In this case, MgSO₄) and the liters of solution.

In the problem:

Moles MgSO₄: 0.32 moles

Liters solution: 5.5L

Molarity is:

0.32 moles / 5.5L =

0.058M is molarity of the solution

6 0

3 years ago

A sample of sodium reacts completely with 0.213 kgkg of chlorine, forming 351 gg of sodium chloride. What mass of sodium reacted

lapo4ka [179]

Answer:

The mass of sodium reacted is 138 grams

Explanation:

Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.

Na = sodium

Cl2 = chlorine gas

Na + Cl2 → NaCl

The balanced equation is

2Na(s) + Cl2(g) → 2NaCl(aq)

Atomic mass of sodium = 23 grams per mol

Atomic mass of chlorine = 35.5 grams per mol

From the chemical equation the molar mass are as follows

Sodium = 2 × 23 = 46 grams

Chlorine = 35.5 × 2 = 71 grams

Sodium chloride = 2 × 23 + 2 × 35.5 = 117 grams

if 46 grams sodium reacted to produce 117 grams of sodium chloride

? grams of sodium react to produce 351 grams sodium chloride

grams of sodium reacted = (351 × 46)/117

grams of sodium reacted = 16146/117

grams of sodium reacted = 138 grams

6 0

3 years ago

Read 2 more answers

When 0.215 mol of a gas is placed into a 34.25 mL container at 125.0°C, 1

horrorfan [7]

Answer:

205.12 atm

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

R = 0.0821 Latm/perK)

T = temperature (K)

n = number of moles (mol)

According to the information in this question;

P = ?

V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L

n = 0.215 mol

T = 125.0°C = 125 + 273 = 398K

Using PV = nRT

P = nRT ÷ V

P = (0.215 × 0.0821 × 398) ÷ (0.03425)

P = 7.025 ÷ 0.03425

P = 205.12 atm

8 0

3 years ago

The iupac name for ch3–ch2–c ≡ c–ch3 is ________

NNADVOKAT [17]

The IUPAC name of the compound ch3–ch2–c ≡ c–ch3 is PEN-2-YNE or 2-PENTYNE.

Attached below is a diagram that fully explains how the name was given and derived.

7 0

4 years ago