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4 years ago

The iupac name for ch3–ch2–c ≡ c–ch3 is ________

Chemistry

1 answer:

NNADVOKAT [17]4 years ago

7 0

The IUPAC name of the compound ch3–ch2–c ≡ c–ch3 is PEN-2-YNE or 2-PENTYNE.

Attached below is a diagram that fully explains how the name was given and derived.

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For IR radiation with û = 1,130 cm 1, v=__THz

Dmitry [639]

Answer: The frequency of the radiation is 33.9 THz

Explanation:

We are given:

Wave number of the radiation, $\bar{\nu}=1130cm^{-1}$

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

$\bar{\nu}=\frac{1}{\lambda}$

where,

$\bar{\nu}$ = wave number = $1130cm^{-1}$

$\lambda$ = wavelength of the radiation = ?

Putting values in above equation, we get:

$1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm$

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, $8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m$

The relation between frequency and wavelength is given as:

$\nu=\frac{c}{\lambda}$

where,

c = the speed of light = $3\times 10^8m/s$

$\nu$ = frequency of the radiation = ?

Putting values in above equation, we get:

$\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}$

$\nu=0.339\times 10^{14}Hz$

Converting this into tera Hertz, we use the conversion factor:

$1THz=1\times 10^{12}Hz$

So, $0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz$

Hence, the frequency of the radiation is 33.9 THz

7 0

3 years ago

Red blood cells are formed by the in the center cavity of the bones.white cells,holes,capillaries,marrow

Anit [1.1K]

Red blood cells are formed by the bone marrow in the center cavity of the bones.

4 0

3 years ago

Which of the following is an indication of a chemical reaction?

vovikov84 [41]

Answer:

All of the above

Explanation:

Their all chemical change

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3 years ago

A 5 Complete the sentences using words from the list. You may use them once, more than once, or not at all.

Mashutka [201]

Answer

Number 1. increase

number 2 . decrease

number 3. decrease

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2 years ago

Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea

REY [17]

Explanation:

Mg(s) + Cr(C2H3O2)3 (aq)

Overall, balanced molecular equation

Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)

To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.

An increase in oxidation number denotes that the element has been oxidized.

A decrease in oxidation number denotes that the element has been reduced.

Oxidation number of Mg:

Reactant - 0

Product - +3

Oxidation number of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.

Oxidized : Mg

Reduced : Cr

7 0

3 years ago