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never [62]
3 years ago
15

How is a shadow created during a lunar or solar eclipse?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
7 0
However, as a result of the Sun's large angular size, solar<span> illumination is only partially blocked in the outer portion of the Earth's </span>shadow<span>, which is given the name penumbra. A penumbral </span>eclipse<span> occurs when the Moon passes through the Earth's penumbra. The penumbra causes a subtle darkening of the Moon's surface.</span>
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given the following list of densities, which material would float in a molten vat of lead provided that they do not themselves m
SIZIF [17.4K]

Answer:

Given the following list of densities, which materials would float in a molten vat of lead provided that they do not themselves melt?

Densities (g/mL): lead = 11.4, glass = 2.6, gold = 19.3, charcoal = 0.57, platinum = 21.4.

glass and charcoal

Explanation:

The density of molten lead is about 10.65Kg/m^3

By Archimedes principles, the buoyancy of an object in a fluid is proportional to the mass of fluid displaced

which in turn is proportional to the object's density

Generally an object well float when placed on a denser medium

glass =2.6, and charcoal =0.57 are both less dense so they will float on Lead

8 0
3 years ago
Based on Gay-Lussac's law, which of the following statements is true for an ideal gas at constant volume and mole amount? (4 poi
Andreas93 [3]
Is Gay-Lussac really gay?
5 0
2 years ago
If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

f_i^o = fugacity of a pure component

X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

f_i=16\text{ bar}

Therefore, the fugacity in the solution is, 16 bar.

4 0
3 years ago
what's the density of an element if a sample has a mass of 43.2 g and a volume of 96.5 mL. (0.45 g/mL)
lisov135 [29]
To find the answer you need to use the formula that will help you to find the density. Density = mass/volume
d = 43.2g/96.5mL = 0.45g/mL
7 0
3 years ago
Pls just help me out the vid is 6 Chemical Reactions That Changed History; need help on no.6. I DON’T EVEN KNOW HOW TO SOLVE IT
GREYUIT [131]

Explanation:

HCL you can do it yourself .try again

4 0
3 years ago
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