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WARRIOR [948]
3 years ago
13

*multiple choice*

Chemistry
1 answer:
galben [10]3 years ago
7 0

1.95  or 2  is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.

The correct answer is option b

Explanation:

Data given:

mass of KNO_{3} = 45.3 grams

volume = 0.225 litre

molarity =?

atomic mass of KNO3 = 101 grams/mole

molarity is calculated by using the formula:

molarity = \frac{number of moles}{volume of the solution}

first the number of moles present in the given mass is calculated as:

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles = \frac{45.3}{101}

0.44 moles of KNO3

Putting the values in the equation of molarity:

molarity = \frac{0.44}{0.225}

molarity = 1.95

It can be taken as 2.

The molarity of the potassium nitrate solution is 2.

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A car traveling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop in 7.5 seconds? What is the cars acc
Marianna [84]

Answer:

The acceleration is: 4m/s^2

Explanation:

Given

u = 30.0m/s --- The initial velocity

t = 7.5s --- time

v = 0m/s -- The final velocity

Required

Determine the acceleration

To do this, we make use of the first equation of motion

v = u - at

We used negative because the car was coming to stop.

This gives:

0 = 30 - 7.5 * a

0 = 30 - 7.5a

Collect like terms

7.5a = 30

Solve for a

a = \frac{30}{7.5}

a = 4m/s^2

6 0
3 years ago
How many Liters are in 1.245 x 10​ 6​mL?
Kamila [148]
1245 liters because you move the decimal place over to the right six times
4 0
3 years ago
At which electrade in a voltaic cell does redaction always occar?​
yanalaym [24]

Answer:cathode

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7 0
3 years ago
How much heat is needed to change the temperature of 5g of water from 20 oC to 37 oC?
Dafna1 [17]

Answer:

The answer to your question is Q = 355.64 J

Explanation:

Data

Heat = Q = ?

Temperature 1 = T1 = 20°C

Temperature 2 = T2 = 37°C

mass = m = 5 g

Specific heat = Cp = 4.184 J/g°C

Formula

Q = mCp(T2 - T1)

-Substitution

Q = (5)(4.184)(37 - 20)

-Simplification

Q = (5)(4.184)(17)

-Result

Q = 355.64 J

5 0
3 years ago
Read 2 more answers
A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec
koban [17]

Answer:

Ca^{2+}  and  Co^{2+}

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, Ca_2 and Co_2

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding Li_2SO_4 to it precipitation takes place.

Precipitate is as follows,

Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)

Thus,

Ca^2^+ is present

When Li_3PO_4 is added again precipitation takes place.

Therefore the reaction is as follows,

Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)

Therefore,

Ca^{2+}  and  Co^{2+} are present in the solution

3 0
3 years ago
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