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Bezzdna [24]
4 years ago
5

How would scientists with Viewpoint #1 respond to the description the herpes virus?

Biology
2 answers:
I am Lyosha [343]4 years ago
6 0

Answer:

A virus is alive; it can respond and/or adapt to changes in the environment.

Explanation:

Herpes simplex virus 1 is a sexually transmitted virus that causes genital herpes.The herpes virus is contagious can be spread through contact with saliva, such as sharing drinks. The virus is alive and responds to changes in environment by adapting to living in body fluids.

REY [17]4 years ago
6 0

Answer: C. A virus is alive; it can respond and/or adapt to changes in the environment

Explanation:

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S waves DO NOT have the following characteristic
Wittaler [7]
It is A hope this helps
4 0
4 years ago
Explain how the progression of cells past sequential cell cycle checkpoints and the activity of enzymes such as separase is cont
bixtya [17]

Answer:

In multicellular organisms, which begin their life with an egg or zygote cell, mitotic cell division is important in the development and maintenance of the various tissues, organs and systems that form it. The new cells caused by mitosis are genetically identical to the stem cell; This is achieved thanks to complex regulatory mechanisms that ensure the integrity of the genomic material and its proper segregation.

Explanation:

Segurine is important because it is responsible for keeping sequestered protease separase; when it is released, thanks to the degradation of segurin, the degradation of the cohesin that holds the sister chromatids together takes place. This cohesin allows chromosomal segregation, while degradation of cyclin results in the inactivation of CDK1 (cyclin dependent kinase).

When the alignment of the chromosomes does not satisfy the SAC (spindle assembly control point), the signal from non-anchored kinetocores induces protein recruitment to the control point. This signal leads to the formation of two independent complexes. The union of the two complexes will lead to the formation of a mitotic control complex. In this way, the segurin will not be marked for degradation and the separase will not be released and the chromosomes will not secrete until the requirements of the SAC are met.

7 0
3 years ago
Explain the 3 steps you would need to calculate the density of a marble
mart [117]
1 fill the beaker with water
2 check the amount you have
3 drop the marble in and subtract the original amount with the one you have now
5 0
3 years ago
Which form of hypoxia occurs when body cells are unable to use o2 even though adequate amounts are delivered? (this type of hypo
Oksana_A [137]

Histotoxic hypoxia, which happens whenever body cells are not able to utilize oxygen while receiving sufficient amounts, is typically caused by metabolic toxins like cyanide.

What is hypoxia?

  • Hypoxia is a state in which there is insufficient oxygen reaching the tissues throughout the system or a specific area of the body.
  • Although fluctuations in arterial concentrations of oxygen are frequently associated with clinical conditions, they can also occur naturally during severe physical activity or hypoventilation training.

When does Histotoxic hypoxia occur?

When the supply of gas entering the cell is adequate, but the cells are unable to utilize the oxygen properly due to deactivated oxidative phosphorylation enzymes, histotoxic hypoxia develops. Ingestion of cyanide may result in this.

Learn more about hypoxia here:

brainly.com/question/14570337

#SPJ4

3 0
2 years ago
In trout, Gene A affects body color and yellow color (allele a) is recessive to red. In a particular river system you find that
hjlf

Answer:

The frequency of the dominant A allele is 0,4 or 40%.

Explanation:

In this population, we have:

- "A" red body color Dominant

- "a" yellow doy color Recessive

So, individuals AA and Aa will be red and trouts aa will be yellow.  In this case, 64% of the fish are red, so they are AA or Aa.

If the population is in Hardy-Weinberg equilibrium the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}=frequency of AA

2pq= frequency of Aa

q^{2}=frequency of aa

It is known that 64% of population is red, in other words:

p^{2}+2pq=0,64

Or AA+Aa=0,64

So, it is possible to find the value of q^{2} (aa):

p^{2}+2pq+q^{2}=1

(0,64)+q^{2}=1

q^{2}=1-0,64q^{2}=0,36

Now, there are two alleles in this population, therefore their frequencies will be:

p+q=1

So, from q^{2} it is possible to find q and p:

q=\sqrt{q^{2} }

q=\sqrt{0,36}

q=0,6

And:

p+q=1\\p=1-q\\p=1-0,6\\p=0,4

7 0
3 years ago
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