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maks197457 [2]
3 years ago
13

Determine if the following systems of equations have one, none or infinitely many solutions.

Mathematics
1 answer:
kolezko [41]3 years ago
3 0

Answer: A. Infinite number of solutions

Step-by-step explanation:

The given system of equations is expressed as

x + 3y = 5- - - - - - - - - - - - - -1

4x + 12y = 20- - - - - - - - - - - 2

We would apply the method of substitution. From equation 1, we would make x the subject by subtracting 3y from the left hand side and the right hand side of the equation. It becomes

x + 3y - 3y = 5 - 3y

x = 5 - 3y

Substituting x = 5 - 3y into equation 2, it becomes

4(5 - 3y) + 12y = 20

20 - 12y + 12y = 20

20 = 20

Therefore, the system of equations has an infinite number of solutions because as many values of x and y that satisfy the first equation, they would also satisfy the second equation.

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