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3 years ago

(y − 3)^2 = 4(x − 5), (6, 1). Find an equation of the tangent line to the graph at the given point.

Mathematics

1 answer:

Mandarinka [93]3 years ago

4 0

Answer:

y=x−1. Explanation: (y−3)2=4(x −5). Expanding: y2−6y+9=4x−20. y2−6y−4x=− 29. Differentiating implicitly: 2ydydx−6dydx−4=0.

y=x−1 Explanation: (y−3)2=4(x−5) Expanding: y2−6y+9=4x−20 y2−6y−4x=−29 Differentiating implicitly: 2ydydx−6dydx−4=0 Factor: ... More

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2 years ago

Sketch the graph of y =sine3x

IgorLugansk [536]

The graph of $\mathbf{y=\sin{3x}}$ is given by,

Here given the function is $y=\sin{3x}$

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1 year ago

For one month Siera calculated her home town's average high temperature in degrees Fahrenheit. She wants to convert that tempera

Lana71 [14]

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3 years ago

Read 2 more answers

0.75y-1.5y+0.5=5 I need answers to this asap

Mnenie [13.5K]

Answer:

y = -6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

0.75y−1.5y+0.5=5

0.75y+−1.5y+0.5=5

(0.75y+−1.5y)+(0.5)=5(Combine Like Terms)

−0.75y+0.5=5

Step 2: Subtract 0.5 from both sides.

−0.75y+0.5−0.5=5−0.5

−0.75y=4.5

Step 3: Divide both sides by -0.75.

Hope this helps!

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2 years ago