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Burka [1]
3 years ago
5

(y − 3)^2 = 4(x − 5), (6, 1). Find an equation of the tangent line to the graph at the given point.

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

y=x−1. Explanation: (y−3)2=4(x −5). Expanding: y2−6y+9=4x−20. y2−6y−4x=− 29. Differentiating implicitly: 2ydydx−6dydx−4=0.

y=x−1 Explanation: (y−3)2=4(x−5) Expanding: y2−6y+9=4x−20 y2−6y−4x=−29 Differentiating implicitly: 2ydydx−6dydx−4=0 Factor: ... More

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3 years ago
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Serggg [28]

y = (x - 2)(x + 5)    First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

y = x² + 3x - 10


Next I would plug in a number for x to find its y value. I will plug in 0

y = 0² + 3(0) - 10

y = -10

(0, -10)   [this is the y-intercept (the y value when x = 0)]


Your answer is Graph A because the y-intercept is (0,-10)

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Solve the following equation for x<br><br> 5(x - 1) = -45
abruzzese [7]

Answer:

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Hope that helps

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3 years ago
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