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Burka [1]
3 years ago
5

(y − 3)^2 = 4(x − 5), (6, 1). Find an equation of the tangent line to the graph at the given point.

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

y=x−1. Explanation: (y−3)2=4(x −5). Expanding: y2−6y+9=4x−20. y2−6y−4x=− 29. Differentiating implicitly: 2ydydx−6dydx−4=0.

y=x−1 Explanation: (y−3)2=4(x−5) Expanding: y2−6y+9=4x−20 y2−6y−4x=−29 Differentiating implicitly: 2ydydx−6dydx−4=0 Factor: ... More

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Take the normal vector to S to be

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\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1\bigg(2u^2v+(u+2v^2)(8-u^2-v^2)\bigg)\,\mathrm du\,\mathrm dv=\boxed{\frac{1553}{180}}

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What fraction of 120 is 45
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Step-by-step explanation:

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