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Lady bird [3.3K]
3 years ago
12

Which expression is the same as 6 times 52?

Mathematics
1 answer:
wel3 years ago
7 0

Answer:

B. 6(50+2)

Step-by-step explanation:

50 + 2 = 52

Then we are to multiple 6 by 52, resulting in the same original equation as well as the same solution.

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Don put $4,000 in a savings account with an interest rate of 4% for three years. If the interest is compounded annually, how muc
miskamm [114]

Answer:

$4,499.46

Step-by-step explanation:

We can use the compound interest formula for this problem:

A=P(1+\frac{r}{n} )^{nt}

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, lets change 4% into a decimal:

4% -> \frac{4}{100} -> 0.04

Now lets plug the values into the equation as shown below:

A=4,000(1+\frac{0.04}{1})^{1(3)}

A=4,499.46

Don will have $4,499.46 at the end of the three years.

4 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

7 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Liula [17]
Hello!

-2x + y = 1
-4x + y = -1

You can subtract these equations from each other to eliminate y

2x = 2

Divide both sides by 2

x = 1

Put this into one of the original equations

-2(1) + y = 1

Combine like terms

-2 + y = 1

Add 2 to both sides

y = 3

The answer is D) (1, 3)

Hope this helps!
6 0
3 years ago
Read 2 more answers
X+y+z=10<br> 6x+y+2z=37<br> y-z=10
garik1379 [7]
Ignore the scribbles
Search up Elimination and substitution

7 0
2 years ago
Elena knows dad 5 servings and granola has 1750 calories how many calories are in one serving of granola
aalyn [17]

If you have information about 5 servings, assuming that all servings have the same calories, the information about one serving is simply obtained by dividing the total by 5.

So, each serving has

\dfrac{1750}{5} = 350

calories

6 0
3 years ago
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