We let the number of years that the two jobs will have the same payment be denoted as t. Equating the wages of these two jobs after t - 1 years will give us an equation of,
22,000 + 4000(t -1) = 26,000 + 2000(t - 1)
The value of t from the generated equation is 3. Therefore, after 3 years the jobs will be paying the same wages.
Make this brainliest please, and thank you
Answer:
P<em>=52in is ya answer!</em>
<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2
y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8
so now you have slope m = 2 and y intercept b = -8
equation
y = 2x - 8
answer
</span><span>a. y = 2x - 8</span>
Answer:
Step-by-step explanation:
hello :
x3^-8=0 means : x3^=8
but : 8 = 2^3
so : x3^= 2^3
x=2
Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 7.5, \sigma = 1.1](https://tex.z-dn.net/?f=%5Cmu%20%3D%207.5%2C%20%5Csigma%20%3D%201.1)
What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{8.6 - 7.5}{1.1}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B8.6%20-%207.5%7D%7B1.1%7D)
![Z = 1](https://tex.z-dn.net/?f=Z%20%3D%201)
has a pvalue of 0.8413
X = 6.4
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{6.4 - 7.5}{1.1}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B6.4%20-%207.5%7D%7B1.1%7D)
![Z = -1](https://tex.z-dn.net/?f=Z%20%3D%20-1)
has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds