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2 years ago

Simplify the expression: 2a+4b=9c

Mathematics

2 answers:

fomenos2 years ago

4 0

Answer:

$a=\frac{9c}{2}-b$

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Alex777 [14]2 years ago

3 0

Answer:

$a=\frac{9c}{2}-b$

Step-by-step explanation:

Isoate the variable to solve

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2. (01.02 MC)<br> Find the value of the expression 4a4 – 2b2 + 40 when a = 2 and b = 7. (5 points)

Sergio039 [100]

Answer:

4x2x4 - 2×7×2 + 40

64 - 28 + 40=76

6 0

3 years ago

Explain what happens to the decimal point in a whole number when you divide it by a power of 10 use this problem with your expla

MatroZZZ [7]

The demical point go's straight up

3 0

3 years ago

Maria es una estudiante de la seccion 7-9 que le gusta leer mucho. Actualmente lee un libro que tiene 288 paginas, silee 12 pagi

dmitriy555 [2]

Responder:

24 días

Explicación paso a paso:

Dado que:

Total de páginas = 288

Número de páginas leídas por día = 12

Número de días que se necesitarán para leer el libro completo:

Total de páginas / número de páginas leídas por día

288/12

= 24

Por lo tanto, a María le tomará 24 días leer el libro completo, si lee 12 páginas del libro por día.

4 0

2 years ago

Help please!!!! Will mark b for right answer

Ronch [10]

Answer:

Step-by-step explanation:

2x+1=71

71-1=70

70÷2=35

therefore x must be 35

5 0

3 years ago

Read 2 more answers

When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f

Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

$P(A) = 0.0286 + 0.1*0.9714 = 0.12574$

Probability of you winning and fireworks going off:

100% of 1/35, so $P(A \cap B) = 0.0286$

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275$

0.2275 = 22.75% probability that you actually won that round

8 0

3 years ago