Your answer is B. I hope this is helpful!
Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
- is the sample proportion.
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of , so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
<h2>Verbal Phrase to Mathematical Phrase</h2><h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
Let that number be .
The quotient of a number and is .
"Increased" is just another term for "plus (+)" so increased by The quotient of a number and is
And it tells us that it is so it must be