2 years ago

In a horse race, how many different finishes among the first 3 places are possible if 7 horses are running? (Exclude ties)

Mathematics

1 answer:

kodGreya [7K]2 years ago

3 0

Answer:

7 x 6 x 5 = 210

Step-by-step explanation:

its a combination's problem.

7 horses are eligible for first place.

6 of those are eligible for 2nd given that one of the 7 finished first.

similarly 5 of the remaining are eligible for 3rd place given 2 horses have taken the first 2 spots.

therefore 7 x 6 x 5 possible combinations = 210 combinations.

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In a horse​ race, how many different finishes among the first 3 places are possible if 7 horses are​ running? (Exclude​ ties)

In a horse race, how many different finishes among the first 3 places are possible if 7 horses are running? (Exclude ties)