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vlabodo [156]
3 years ago
12

Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv

e a problem at an academic bowl. How often will it take Scott more than 4.25 minutes to solve a problem at an academic bowl?
Mathematics
1 answer:
uysha [10]3 years ago
8 0

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(more than 4.25 minutes to solve a problem)

P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

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Please find the general limit of the following function:
valentinak56 [21]

Answer:

The general limit exists at <em>x</em> = 9 and is equal to 300.

Step-by-step explanation:

We want to find the general limit of the function:

\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))

By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.

So, let's find each one-sided limit: the left-hand side and the right-hand side.

The left-hand limit is given by:

<h3>\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))</h3>

Since the given function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

300

Therefore:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300

The right-hand limit is given by:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))

Again, since the function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

=300

Therefore:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Thus, we can see that:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.

8 0
3 years ago
Read 2 more answers
True or false: The variable overhead rate variance uses the same basic formula as the labor rate variance except that the variab
Zanzabum

Answer:

True

Step-by-step explanation:

The variable overhead rate variance refers to the difference in two variables.

The Variables are

1. The actual variable manufacturing overhead

2. The expected variable overhead given the number of hours worked

Labor rate variance is evaluated by

AH(AR - SR)

AH = actual hours

AR = actual rate

SR = standard rate.

The variable overhead rate variance is also calculated the same way except that it replaces the direct labor rates with variable overhead rates

5 0
4 years ago
Which of these terms indicates the exchange of goods and services between countries
kupik [55]
International trade. 
5 0
3 years ago
Multiply. 32√⋅28√⋅3√⋅6√ in simplest radical form, in the box.
PolarNik [594]

Answer:  48\sqrt{7}

Step-by-step explanation:

Given expression, \sqrt{32} \times \sqrt{28}\times \sqrt{3}\times \sqrt{6}

= √(4×8)×√(4×7)×√3×√(3×√2)

= √4×√8×√4×√7×√3×√3×√2 ( because √(m×n)=√m×√n)

=√4×√4×√8×√2×√7×√3×√3

=4×√(4×2)×√2×√7×3

=4×√4×√2×√2×√7×3

=4×2×2×√7×3

=48√7

Thus,\sqrt{32} \times \sqrt{28}\times \sqrt{3}\times \sqrt{6}=48\sqrt{7}


7 0
4 years ago
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Ne4ueva [31]

Answer:

Draw 2 squares as in the picture below

Step-by-step explanation:

U 2 can help me by marking as brainliest.....

4 0
3 years ago
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