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vazorg [7]
3 years ago
10

Pleas help to find a cure for cancer

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0

Answer: Area of Yellow part is 5.365046 ft^{2}

Step-by-step explanation:

Figure show that length of square is 5 ft  and diameter of circle is also, 5 ft.

Here, Red part + Yellow part = Entire square of length of 5ft

Area of red part is area of circle = \pi R^{2}

                                                     = \pi (\frac{5}{2})^{2}

                                                     = 19.634954 ft^{2}

Area of Entire square of length of 5ft  = 5x5 = 25 ft^{2}

Therefore, Area of Yellow part is 25-19.634954=5.365046 ft^{2}

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Based on data from a​ college, scores on a certain test are normally distributed with a mean of 1530 and a standard deviation of
harkovskaia [24]

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0.73% of the scores are greater than 2317.

14.46% of the scores are less than 1190.

38.23% of the scores are between 1351 and 1673.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1530, \sigma = 322

Find the percentage of scores greater than 2317.

This is 1 subtracted by the pvalue of Z when X = 2317. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{2317 - 1530}{322}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927.

So 1-0.9927 = 0.0073 = 0.73% of the scores are greater than 2317.

Find the percentage of scores less than 1190.

This is the pvalue of Z when X = 1190. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1190 - 1530}{322}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446.

So 14.46% of the scores are less than 1190.

Find the percentage of scores between 1351 and 1673.

This is the pvalue of Z when X = 1673 subtracted by the pvalue of Z when X = 1351. So

X = 1673

Z = \frac{X - \mu}{\sigma}

Z = \frac{1673- 1530}{322}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

X = 1351

Z = \frac{X - \mu}{\sigma}

Z = \frac{1351- 1530}{322}

Z = -0.56

Z = -0.56 has a pvalue of 0.2877

So 0.67-0.2877 = 0.3823 = 38.23% of the scores are between 1351 and 1673.

4 0
3 years ago
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