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2 years ago

Pleas help to find a cure for cancer

Mathematics

1 answer:

Dmitry [639]2 years ago

8 0

Answer: Area of Yellow part is 5.365046 $ft^{2}$

Step-by-step explanation:

Figure show that length of square is 5 ft and diameter of circle is also, 5 ft.

Here, Red part + Yellow part = Entire square of length of 5ft

Area of red part is area of circle = $\pi R^{2}$

= $\pi (\frac{5}{2})^{2}$

= 19.634954 $ft^{2}$

Area of Entire square of length of 5ft = 5x5 = 25 $ft^{2}$

Therefore, Area of Yellow part is 25-19.634954=5.365046 $ft^{2}$

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Convert 131 57’ 32” to decimal degree

Arlecino [84]

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Step-by-step explanation:

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2 years ago

Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you

Greeley [361]

Answer:

$(f\circ g)(-5)=85$

Step-by-step explanation:

We are given:

$\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x$

And we want to find:

$(f\circ g)(-5)$

This is equivalent to:

$\displaystyle =f(g(-5))$

So, we will evaluate g(-5) first, which yields:

$\displaystyle g(-5)=(-5)^2+(-5)=25-5=20$

So:

$=f(g(-5))=f(20)$

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3 years ago

Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was

andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, p = 0.42$

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So $\alpha = 0.08$ , z is the value of Z that has a pvalue of $1 - \frac{0.08}{2} = 0.96$ , so $Z = 1.75$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064$

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

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3 years ago

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wlad13 [49]

Answer:

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2 years ago