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TiliK225 [7]
3 years ago
12

V = (pi r^2 h/3)...solve for h​

Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

h = (3×V)/ (pi×r²)

Step-by-step explanation:

v =  \frac{\pi {r}^{2} h}{3}

3 \times v = \pi {r}^{2} h

h =  \frac{3v}{\pi {r}^{2} }

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How do I write a recursive formula for this sequence? 2, 6, 18, 54, 162, ... I already know the common difference is x3.
dmitriy555 [2]
For the sequence 2, 6, 18, 54, ..., the explicit formula is: an = a1 ! rn"1 = 2 ! 3n"1 , and the recursive formula is: a1 = 2, an+1 = an ! 3 . In each case, successively replacing n by 1, 2, 3, ... will yield the terms of the sequence. See the examples below.
4 0
3 years ago
6. <br> Which of the following is the graph of the equation y = −2x2 − 3x + 4?
Stells [14]

Answer:

From the looks of the graph, it looks like the answer will be Letter C. (The last graph).

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  ( − 3 /4 ,  41 /8 )

Focus:  ( − 3 /4 ,  5 )

Axis of Symmetry:  x = − 3 /4

Directrix:  y = 21 /4

x                  y

− 3               − 5

− 2                2

− 3                4

41                8

0                 4

1                 − 1

4 0
3 years ago
The graph shown _____ So, the graph is _____ &lt;(a function/ not a function)
frozen [14]
The first answer is the correct one
6 0
3 years ago
Find the argument of the complex number z=1+iv3
elena-14-01-66 [18.8K]

Given:

The complex number is:

z=1+i\sqrt{3}

To find:

The argument of the given complex number.

Solution:

If a complex number is z=x+iy, then the argument of the complex number is:

\theta=\tan^{-1}\dfrac{y}{x}

We have,

z=1+i\sqrt{3}

Here, x=1 and y=\sqrt{3}. So, the argument of the given complex number is:

\theta =\tan^{-1}\dfrac{\sqrt{3}}{1}

\theta =\tan^{-1}\sqrt{3}

\theta =\tan^{-1}\left(\tan \dfrac{\pi}{3}\right)

\theta =\dfrac{\pi}{3}

Therefore, the argument of the given complex number is \theta =\dfrac{\pi}{3}.

6 0
3 years ago
Graph y = -1/3x + 3<br><br> (( if you could include a picture of the graph that would be great))
Kay [80]
A place I go to graph is go to desmos.  It works well for this. All you have to do is snip the picture of your graph
6 0
3 years ago
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