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k0ka [10]
3 years ago
11

Calculate the mass of na2co3 required to prepare 250ml of 0.5N solution

Chemistry
1 answer:
Nutka1998 [239]3 years ago
3 0
Concentration = 0.5 N
volume = 250 ml = 250 cm^3 = 0.250 dm^3
moles = conc. × vol.
= 0.5 × 0.250
= 0.125
mass = moles × relative molecular mass

so relative molecular mass if Na2CO3
= (23 × 2 ) +( 12 × 1 )+ (16 × 3 )
= 46 + 12 + 48
= 106

mass = 0.125 × 106
= 13.25 g

Hope it helped !!
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