We need an equation that will relate the concentrated mixture and the diluted one. To solve this we use the equation,
M1 V1 = M2 V2
where M1 is the concentration
of the stock solution, V1 is the volume of the stock solution, M2 is the
concentration of the new solution and V2 is its volume.
M1V1 = M2V2
30 % x 6 oz = 20 % x V2
V2 = 9 oz
The volume of the diluted mixture would be 9 oz. Therefore, you will need to add 9 oz - 6 oz = 3 oz of fruit juice to dilute the 30 percent alcohol to 20 percent alcohol.
Answer:
Compounds
Explanation:
Substances in which atoms of two or more elements are chemically combined are called compounds.
A compound is a substance formed when two or more elements are chemically joined.
Given :
Number of moles of CHF₃ is 1.7 .
Solution :
We know, 1 mole of any complex contains 6.022 × 10²³ molecules.
Let, 1.7 moles of CHF₃ contains n numbers of molecules.
So, n = 1.7 × 6.022 × 10²³ molecules
n = 10.2374 × 10²³ molecules
n = 1.0237 × 10²³ molecules
Hence, this is the required solution.
Answer:
The concentration of sucrose will decrease.
Explanation:
The balloon contains 50% sucrose solution.
Diffusion is the net movement of the substance from the region of the higher concentration to the region of the lower concentration.
Given that the membrane is only permeable to water not sucrose. So, movement of sucrose will not take place. <u>When the balloon is placed in a beaker of water, by the process of diffusion, the water moves from beaker to balloon and thus, the balloon will expand and the concentration of sucrose solution will decrease.</u>
Answer:
The emission spectrum is formed when the electrons of a particular atom absorb energy and are excited (in this case by heating), reaching higher energy levels.
You can see it for example with an experiment where we light alcohol mixed with banana chips (it has potassium). The burning alcohol emits heat that makes potassium atoms excite and these in turn emit something red, orange light. If we add for example boric acid you see a green light.
Explanation:
