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ICE Princess25 [194]
3 years ago
8

How would you male 2.0L of O.100M sulfurice acid from a 12.0M stock bottle of sulfurice acid Calc, sketch, and write a summary s

tatement
Chemistry
1 answer:
ozzi3 years ago
7 0

<u>Answer:</u> The volume of stock solution needed is 0.016 L

<u>Explanation:</u>

To calculate the volume of stock solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock solution

M_2\text{ and }V_2 are the molarity and volume of diluted solution

We are given:

M_1=12M\\V_1=?L\\M_2=0.10M\\V_2=2L

Putting values in above equation, we get:

12\times V_1=0.1\times 2\\\\V_1=0.016L

Hence, the volume of stock solution needed is 0.016 L

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The average propane cylinder for a residential grill holds approximately 18 kg of propane. How much energy (in kJ) is released b
brilliants [131]
Combustion is a chemical reaction between a fuel and an oxidant, oxygen, to give off combustion products and heat. Complete combustion results when all of the fuel is consumed to form carbon dioxide and water, as in the case of a hydrocarbon fuel. Incomplete combustion results when insufficient oxygen reacts with the fuel, forming soot and carbon monoxide. 

The complete combustion of propane proceeds through the following reaction:
C_{3} H_{8} + 5O_{2} --> 3CO_{2} + 4H_{2}O

Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic. 

The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.

 14.50 kg propane  x <u> 1000 g </u> x <u>  1 mole propane   </u>  x <u>  2220 kJ  </u>   
                                     1 kg              44.1 g                     1 mole

= 729,931.97 kJ
8 0
3 years ago
what is the volume of a sample of liquid mercury that has a mass of 76.2 g, given that the density of mercury is 13.6 g/ml?
lilavasa [31]
24 square root . i know im wrong but so what 
6 0
3 years ago
When magnesium chloride reacts with water, 5.85 L HCl(g) is produced.
amid [387]

Answer: How many moles of HCl was produced?

⇒ 0.261 moles of HCl

How many moles of MgCl2 reacted?

⇒ 0.131 moles of MgCl2

What mass of MgCl2 reacted?

⇒ 12.4 g MgCl2

Explanation:

i just did it

3 0
3 years ago
Read 2 more answers
Which of the subshells below do not exist due to the constraints upon the angular momentum quantum number?A) 2dB) 2sC) 2pD) all
Gnom [1K]

Answer:

  • Option A): <em>Due to the constraints upton the angular momentum quantum number, the subshell </em><u><em>2d</em></u><em> does not exist.</em>

Explanation:

The <em>angular momentum quantum number</em>, identified with the letter l (lowercase L),  number is the second quantum number.

This number identifies the shape of the orbital or <em>kind of subshell</em>.

The possible values of the angular momentum quantum number, l, are constrained by the value of the principal quantum number n: l can take values from 0 to n - 1.

So, you can use this guide:

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number, n                 quantum number, l

         1                                      0                             s

         2                                     0, 1                          s, p

         3                                     0, 1, 2                      s, p, d

Hence,

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  • 2s (option B) is possible: n = 2, l = 0

  • 2p (option C) is possible: n = 2, l = 1

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4 years ago
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wariber [46]

Answer:

Time

Explanation:

8 0
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