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Vika [28.1K]
3 years ago
5

calculate the concentration in parts per million (ppm) of DDT if a sample size of 2000 g contained 0.050 g DDT

Chemistry
1 answer:
Firlakuza [10]3 years ago
4 0

Answer:

= 25 ppm

Explanation:

  • PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in a 1000 mL, which equivalent to 1 mg per liter.

Given; a sample size of 2000 g contained 0.050 g DDT

It means, 2000 mL sample contained 50 mg DDT

Therefore in ppm we get;

= 50 mg/ 2 L

= 25 mg/L

<u>= 25 ppm</u>

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Explanation:

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T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

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T^o_b = boiling point of pure carbon disulfide= 46.2^oC

k_b = boiling point constant  =2.34^0Ckg/mol

m = molality

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Now put all the given values in the above formula, we get:

(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}

T_b=49.1^0C

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