Answer:
60.0 mL
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
6.33 g CuNO₃
0.840 M Solution
<u>Step 2: Identify Conversions</u>
1 L = 1000 mL
Molar Mass of Cu - 63.55 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuNO₃ - 63.55 + 14.01 + 3(16.00) = 125.56 g/mol
<u>Step 3: Convert</u>
<u />
= 0.050414 mol CuNO₃
<u>Step 4: Find volume</u>
- Substitute: 0.840 M = 0.050414 mol / x L
- Multiply <em>x</em> on both sides: (x L)(0.840 M) = 0.050414 mol
- Divide <em>M</em> on both sides: x L = 0.060017
<u>Step 5: Convert</u>
<u />
= 60.0168 mL
<u>Step 6: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
60.0168 mL ≈ 60.0 mL