The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer:
The value of x is 
Step-by-step explanation:
we know that
Applying the tangent-secant theorem

substitute the values and solve for x



using a graphing tool
to solve the quadratic equation
The solution is 
see the attached figure
Answer:
A
Step-by-step explanation:
y=3/4x+4 best represents the line shown below. Because the slope of this graph is 3/4, and the y-intercept is positive 4. Remember that slope=rise/run. You can find the slope very easily by counting, 3 upwards and 4 rightwards.
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