Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
Answer:
it would be $16 off 40 so the pants would be $24
I think the answer is A.
So, when you are first given a set of data, order the numbers from least to greatest:
3, 4, 4, 5, 5, 5, 6, 6, 6, 8, 8, 8, 8, 9, 10, 10
Now we have to find the median...
3, 4, 4, 5, 5, 5, 6, (6, 6) 8, 8, 8, 8, 9, 10, 10
There is an even amount, so we have to add the 2 numbers in the middle and then divide by 2 to get the median. 6 + 6 = 12 /2 = 6
6 is the median. Now we have to find our minimum, maximum, and quartiles.
(3, 4, 4, (5, 5), 5, 6, 6) (6, 8, 8, (8, 8), 9, 10, 10)
Min= 3 , 1st quartile = 5, 2nd Quartile ( Median ) = 6 , 3rd Quartile = 8, Maximum = 10.
So you would plot the dots and connect the lines and make the box!
Hope this helps!
