Answer:
1/2 o 50%
Step-by-step explanation:
debemos partir de la presuncion que un bebe puede ser niño o niña uinicamente, o sea la P(niño) + P(niña) = 1
no existen los bebes que son niños y niñas al mismo tiempo, eso quiere decir que es una opcion o la otra
P(niña) = 1 - P(niño) = 1 - 1/2 = 1/2 = 0.5 = 50%
Answer:
4 cups
Step-by-step explanation:

40x=356000 x= 8900 applications
you make x the number of total applications
5x² + 5x + 2x + 2
5x(x + 1) + 2(x + 1)
(5x + 2)(x + 1)
Answer:

And if we want to find
we can use this formula from the definition of independent events :

And the best option would be:

Step-by-step explanation:
For this case we have the following events A and B and we also have the probabilities for each one given:

And if we want to find
we can use this formula from the definition of independent events :

And the best option would be:
