Question

Factoring Trinomials

Answer 1

25 a² + 20 ab +  4 b²

for formula $a^x+bx^ky^k+cy ^{2k }$ find  u,v such that: u.v = a

and u+v = b  then  group according to $(ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )$

= $(25a^2+10ab)+(10ab+4b^2)$

factor out 5a from : $25a^2+10ab : 5a(2b+5a)$

factor out 2b from : $10ab+4b^2: 2b(2b+5a)$

= $5a(2b+5a) + 2b(2b+5a)$

factor out : $(5a+2b)$

= $(5a+2b)(5a+2b)$

Refine:

$(2b+5a)^2$

hope this helps!.