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enot [183]
4 years ago
6

Factoring Trinomials

Mathematics
1 answer:
alexandr402 [8]4 years ago
3 0
25 a² + 20 ab +  4 b²

for formula a^x+bx^ky^k+cy ^{2k } find  u,v such that: u.v = a

and u+v = b  then  group according to (ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )

= (25a^2+10ab)+(10ab+4b^2)

factor out 5a from : 25a^2+10ab : 5a(2b+5a)

factor out 2b from : 10ab+4b^2: 2b(2b+5a)

= 5a(2b+5a) + 2b(2b+5a)

factor out : (5a+2b)

= (5a+2b)(5a+2b)

Refine:

(2b+5a)^2

hope this helps!.


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