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Artyom0805 [142]
4 years ago
5

Why does an object appear to be moving faster as it moves away from the axis of rotation​

Physics
1 answer:
S_A_V [24]4 years ago
4 0

Answer:

I suppose that this is a problem of rotation with constant angular velocity.

This can be answered with arcs.

Suppose that we have a circle of radius R, and an angle A (A expressed in radians)

The length of that arc will be:

L = R*A

Now, a rotating object that rotates at a constant angular velocity, in a time t moves an angle A.

so if this object is moving in a circle of radius R, in the time t the distance traveled is the same that we found above.

L = R*A

Now, if the object moves away from the axis of rotation, we have that the radius of the circle R increases, then also does the value of L (the distance traveled in the time t)

Then, when the object moves away from the axis of rotation, in the same time t, the distance traveled will be higher, which means tath the tangential velocty increased (regardless the fact that the angular velocity is constant)

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A girl pushes on a table with a 5-newton force directed to the east. Her friend pushes on the same table with a 10- newton force
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Think like this: 10 is twice as much as 5.

Answer A pushes 2 squares east and 4 squares sout, being doubled just as 10 is to 5. Happy to help :)

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3 years ago
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8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?
Sidana [21]

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

q_1=q_2=+1C are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N

8 0
3 years ago
A particle is traveling in the positive direction along an x axis, at a constant 5 m/s. Which of the following describes the par
vaieri [72.5K]
1-zero as the velocity is constant
3 0
3 years ago
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sineoko [7]
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7 0
3 years ago
Object A has 25 J of kinetic energy. Object B has one-quarter the mass of object A.By what factor does the speed of each object
Natalka [10]

Answer:

The speed of object B is 2 times of speed of object A.

Explanation:

Given that,

Kinetic energy of object A = 25 J

Mass of object B m_{B}=\dfrac{1}{4}m_{A}

Work done = -20 J

We need to calculate the factor of the speed of the object

Suppose the final kinetic energy is same for both object.

K.E_{f_{A}}=K.E_{f_{B}}

\dfrac{1}{2}m_{A}v_{A}^2=\dfrac{1}{2}m_{B}v_{B}^2

Put the value into the formula

\dfrac{1}{2}m_{A}\times v_{A}^2=\dfrac{1}{2}\times\dfrac{1}{4}m_{A}\times v_{B}^2

\dfrac{v_{A}}{v_{B}}=\dfrac{1}{2}

v_{A}=\dfrac{1}{2}v_{B}

v_{B}=2v_{A}

Hence, The speed of object B is 2 times of speed of object A.

4 0
3 years ago
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