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3 years ago

Which example most effectively illustrates the dual nature of light?

Physics

2 answers:

Aleksandr-060686 [28]3 years ago

7 0

Answer:

The correct answer is option a. "cameras that use photographic film".

Explanation:

It is considered that light has a dual nature because it act as a particle and as a wave. The fact that cameras use photographic film to work illustrates the dual nature of light. The photographic film captures the image formed by light's reflection, and it does so by using a sensitive element such as silver halide that changes the structure when it reacts to the light photons (particle). Additionally to reacting with the particle, the films have layers of emulsion that produces the color when it interacts with different wavelengths of the light (wave).

AveGali [126]3 years ago

4 0

The answer is A. Cameras that use photographic film.
Light has both properties of a wave and a particle.<span>Light can be treated like a wave, but its energy is distributed in discrete packets called </span>photons. Light can appear in different wavelength -- the greater the wavelength, the lesser energy it emits. This explains the existence of color! A <span>chemical change occurs in the photographic detectors that are coated on the film when the energy in the photon of light hits the film. This process is called photochemistry. </span>

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3 years ago

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Explanation:

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4 years ago

Read 2 more answers

With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be

jeyben [28]

Question:

Assumptions

Voltage of battery = 24 V

Resistance on the right,20Ω parallel to 10 Ω resistor

Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance = $\frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega$

Current out of voltage, I = Voltage/(total resistance)

= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A

Therefore, with the switch opened, we get

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Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

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