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Delicious77 [7]
4 years ago
5

Farming and fishing are ways of harvesting the oceans A.sodium chloride B.oil and natural gas C. Living resources D.nonrenewable

resources
Physics
2 answers:
xeze [42]4 years ago
5 0
I think it is C. but im not sure 

hope this helps
dedylja [7]4 years ago
3 0

Answer: C. Living resources

Explanation:

Farming and fishing requires aquaculture of a diversity of sea animals which is capable enough to commercially provide a huge economical benefit by selling these animals as a source of food, using fish oil for medicines, using coral reef in preparation of medicines and other for meeting the requirement of other useful needs.  

On the basis of the above explanation,  this can be said that Farming and fishing are ways of harvesting the oceans for the living resources.

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1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}

Where;

v = The image distance from the lens

We get;

v = \dfrac{u \times f}{u - f}

Therefore;

v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0
3 years ago
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