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xz_007 [3.2K]
3 years ago
5

¿ que es una onda mecánica y como es su gráfica? ¿qué es la amplitud y la frecuencia ?

Physics
1 answer:
Ainat [17]3 years ago
8 0

Una onda mecánica es una onda que no es capaz de transmitir su energía a través del vacío. Las ondas mecánicas requieren un medio para transportar su energía de un lugar a otro. Una onda de sonido es un ejemplo de onda mecánica. Las ondas sonoras son incapaces de viajar a través del vacío. ¡su gráfico está debajo! La amplitud es un parámetro importante de las ondas y es el desplazamiento máximo de puntos en una onda. Dicho de otra manera, la amplitud es la distancia vertical entre un pico o un valle y el punto de equilibrio. La frecuencia es el número de ciclos de ondas que pasan por un punto por unidad de tiempo.

¡Espero que esto te ayude! Buena suerte y que tengas un gran día. :)

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Maxwell shoots a rubber band at his friend Jimmy. Which type of energy is converted into kinetic energy?
Leokris [45]

A stretched rubber band is storing <em>elastic potential energy. (A)</em>

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3 years ago
The speed of sound in air is around 330 m/s. If a bat emits a single high-pitched ‘click’ of sound in a cave that is 25m wide, c
Bingel [31]

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

4 0
2 years ago
Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into th
satela [25.4K]

The tank has a volume of \dfrac\pi3R^2H, where H=6\,\rm m is its height and R=\dfrac d2=2\,\rm m is its radius.

At any point, the water filling the tank and the tank itself form a pair of similar triangles (see the attached picture) from which we obtain the following relationship:

\dfrac26=\dfrac rh\implies r=\dfrac h3

The volume of water in the tank at any given time is

V=\dfrac\pi3r^2h

and can be expressed as a function of the water level alone:

V=\dfrac\pi3\left(\frac h3\right)^2h=\dfrac\pi{27}h^3

Implicity differentiating both sides with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9h^2\,\dfrac{\mathrm dh}{\mathrm dt}

We're told the water level rises at a rate of \dfrac{\mathrm dh}{\mathrm dt}=20\,\frac{\rm cm}{\rm min} at the time when the water level is h=2\,\mathrm m=200\,\mathrm{cm}, so the net change in the volume of water \dfrac{\mathrm dV}{\mathrm dt} can be computed:

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9(200\,\mathrm{cm})^2\left(20\,\dfrac{\rm cm}{\rm min}\right)=\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}

The net rate of change in volume is the difference between the rate at which water is pumped into the tank and the rate at which it is leaking out:

\dfrac{\mathrm dV}{\mathrm dt}=(\text{rate in})-(\text{rate out})

We're told the water is leaking out at a rate of 10,500\,\frac{\mathrm{cm}^3}{\rm min}, so we find the rate at which it's being pumped in to be

\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}=(\text{rate in})-10,500\,\dfrac{\mathrm{cm}^3}{\rm min}

\implies\text{rate in}\approx289,753\,\dfrac{\mathrm{cm}^3}{\rm min}

4 0
3 years ago
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Answer:

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4 0
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Answer:

Current through the surface at t = 1.1 s is 21.37 A.

Explanation:

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t is in seconds

q=5.2t^3+2.5t+6.5

The rate of change of electric charge is called electric current. It is given by :

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At t = 1.1 s, Current,

I=15.6(1.1)^2+2.5\\\\I=21.37\ A

So, the instantaneous current through the surface at t = 1.1 s is 21.37 A.

3 0
3 years ago
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