Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t -
) And
yB = 8 sin(2t -
)
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( -
+
)
Or, phase difference between yA and yB = 
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is
Answer
Answer:
hope this helps you out good luck with your math
Answer:
multiply the chances
1/2 (every other number is even right)
1/2 x 1/6 (if it is a normal dice) = 1/12
1/12 chance
Step-by-step explanation:
30 - 5*4 +2 = 12
30 - 20 +2 = 12
10+2 = 12
12 = 12
1/2DF = EF
1/2(2y) = 8y - 3
y = 8y - 3
- Subtract 8y from both sides.
-7y = -3
y = 3/7
- Plug 3/7 for y into DF and EF.
DF: 2(3/7) = 6/7
EF: 8(3/7) - 3 = 24/7 - 3 = 3/7
EF = DE because they are bisected, so DE = 3/7