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3 years ago

What are the intercepts of the line 5x+y=20

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

If you rewrite the equation to where y would be by itself it would be y=-5×+20.
The y intercept would be 20 and the x intercept would be 4

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Rafael want to buy the same number of gifts bags and bows gifts bags are sold in packs of 6. Bows are sold in packs of 9. What i

GenaCL600 [577]

Answer:

Rafael should buy 9 gift bags and 6 bows packet so, that she can have SAME NUMBER OF ITEMS, i.e 54.

Step-by-step explanation:

The gift bags are sold in the packs of 6.

So, the number of gift bags in 1 packet = 6 gift bags

The number of gift bags in 2 packet = 6 x 2 gift bags = 12 gift bags

The number of gift bags in 3 packet = 6 x 3 gift bags = 18 gift bags

And continuing similarly, we get

The number of gift bags in 9 packet = 6 x 9 gift bags = 54 gift bags.. (1)

The bows are sold in the pack of 9.

So, the number of bows in 1 packet = 9 bows

The number of bows in 2 packet = 9 x 2 bows = 18 bows

The number of bows in 3 packet = 9 x 3 bows = 27 bows

And continuing similarly, we get

The number of bows in 6 packet = 9 x 6 bows = 54 bows... (2)

Here, comparing both equations (1) and (2) , we get

The number of gift bags = 54 = The number of bows.

Hence, Rafael should buy 9 gift bags and 6 packet of bows so, that she can have SAME NUMBER OF ITEMS, i.e 54.

8 0

3 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

Thus the daily expense in dollars can be given by = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

Tour duration now = $(x+4)$ days

On extension, his daily expense is cut by $3

New daily expense in dollars = $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

You spend $20 total on tubes of paint and disposable brushes for an art project. Tubes of paint cost $4.00 each and paintbrushes

hram777 [196]

You are buying 2 items so let's use two different variables to represent each:
p = number of tubes of paint
b = number of disposable brushes
cost = price per item × number of items
Equations from information given:
4p + 0.50b = 20 ← from the first 2 sentences
2p = b ← if there are twice as many brushes as paint tubes you need 2 times paint tubes to equal number of brushes
Solve the problem by using substitution... 1b equals 2p so replace b with that:
4p + 0.50(2p) = 20
4p + 1p = 20 ← 0.50 is half so half of 2p is 1p
5p = 20 ← combine like terms
p = 4 ← divide both sides of the equation by 5
Recall the equation 2p = b replace p with 4
2(4) = b
8 = b
ANSWER:
You purchased 4 tubes of paint and 8 disposable brushes.

8 0

3 years ago

Que es un variable? (De matemáticas)

dsp73

Answer:

$\huge\boxed{Que \ es \ un \ variable \ ?\hookleftarrow}$

✐ En matemáticas, una variable es un símbolo que funciona como marcador de posición para expresiones o cantidades que pueden variar o cambiar; se utiliza a menudo para representar el argumento de una función o un elemento arbitrario de un conjunto. Además de los números, las variables se utilizan comúnmente para representar vectores, matrices y funciones.

6 0

2 years ago