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3 years ago

What are the intercepts of the line 5x+y=20

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

If you rewrite the equation to where y would be by itself it would be y=-5×+20.
The y intercept would be 20 and the x intercept would be 4

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Find the volume of the solid. Round to the nearest tenth, if necessary.

puteri [66]

Answer:

I think it is correct

Step-by-step explanation:

length=10m

height=12

breadth = 3m

volume = l*b*h

10*12*3

120*3

360m^3

3 0

2 years ago

A 2-quart carton of apple juice costs $4.56. What is the price per cup?

Ede4ka [16]

Answer:

57 cents

$0.57

Step-by-step explanation:

1 quart= 4 cups

2 quarts=8 cups

8 cups=4.56

Divide each side by 8

1 cup=0.57

Hope this Helps!

8 0

2 years ago

A youth sports league held various fundraisers. They received $350 from a car wash, $337 from a bake sale, and $490 from a used

mina [271]

Given that the received amount was $350 from a car wash, $337 from a bake sale, and $490 from a used equipment sale.

Also, the interest rate is 2.2 % and the time period is 3 years.

Thus, the total amount is as follows:

$\begin{gathered} \text{Total amount = 350+337+490} \\ \text{Total amount = }1177 \end{gathered}$

Next, the accumulated amount can be calculated as follows:

$\begin{gathered} Accumulated\text{ amount = P(1+}\frac{R}{100})^n \\ Accumulated\text{ amount }=\text{ 1177(1+}\frac{2.2}{100})^3 \\ Accumulated\text{ amount }=1177(\frac{102.2}{100})^3 \end{gathered}$

Further, solve the obtained result as follows:

$\begin{gathered} Accumulated\text{ amount }=\text{ 1177}\times(1.022)^3 \\ Accumulated\text{ amount }=1177\times1.067 \\ Accumulated\text{ amount }=1256.40 \end{gathered}$

Thus, the league will have $1256.40 in their account after 3 years.

5 0

1 year ago

Multiple Choice: Please select the best answer

aliya0001 [1]

The answer is D.Exponent

5 0

3 years ago

Read 2 more answers

Sin(x−y)/sinxsiny= coty - cotx<br>

andrew-mc [135]

$x = 0 \\ \\ \sin^{2}(y) \sin( \frac{x - y}{ \sin(x)} ) - \sin(x) \cos(y)\cos(x)\sin(y)= 0$