Answer:
a) add a dummy stroke to make the problem as an assignment problem of adding 5 strokes to 5 swimmers. see first attachment.
b) applying the Hungarian method.
4.8 0 0.9 4.1 2.5
10.3 0 9.1 1.6 8.7
4.8 0 10.4 1.9 5.1
2.8 0 3.2 2.1 4.7
0 0 0 0 0
Deduct the smallest element in each column from the other elements of the column.
2 0 0 2.5 0
7.5 0 8.2 0 6.2
2 0 9.5 0.3 2.6
0 0 2.3 0.5 2.2
0 0 0 0 0
Which implies:
2 8.2 2.5 6.2
7.5 9.5 0.3 2.6
2 2.3 0.5 2.2
33.8 + 34.7 + 28.5 + 29.2 = 126.2
David = Back Stroke
tony = Breast Stroke
Chris = Butterfly
Carl = Free Style
When a car ends up 0 m from its starting point.....this means that the distance driven is the same distance when coming back
The car first travels a distance of 9 meters, and then travels 9 meters in the opposite direction <=== 9 - 9 = 0
<span>V(pyr.)=1/3V(prism)=1/3(144)=48 cubic inches.</span>
Answer:
a) .3607.
b) See explanation below.
Step-by-step explanation:
The probability that the flight of the airline arrives on time is .775. The problem tells us that the events are independent and asks us what is the probability that 4 flights arrive on time.
Since the probability is independent we can simply multiply the probabilities of each flight arriving on time.
Probability that all 4 flights arrive on time = (.775)(.775)(.775)(.775) = 0.3607.
b) How realistic it is to assume that the on-time arrivals are independent?
This assumption is not very realistic, considering that if one flight is not on time, it will obviously affect all the other flights since the planes are constantly connected to each other and if the flights are using one same plane, the fact that this plane is not on-time will affect the next flight.