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3 years ago

Write an equation in slope-intercept form for the line with slope -3/4 and y intercept -3

1 answer:

7 0

Slope intercept form is simply
$y = mx + b$

where y and x are the things we see on the graph
m is the slope
and b is the y-intercept

the y-intercept is just what y is equal to when x is 0, so right at the middle of the graph.

so just go ahead and if in!

$y = - \frac{3}{4} x - 3$

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yan [13]

Answer:

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Step-by-step explanation:

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3 years ago

Which number in the monomial 125x^18y^3z^25 needs to be changed to make it a perfect cube

Oksana_A [137]

Hi,

You just have to change z^25 to z^24 or z^27.

$125x^{18}y^3z^{24}=(5x^6*y*z^8)^3$

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3 years ago

Read 2 more answers

If you divide 6! by 4! you are evaluating P(6, 4)

Aleks [24]

When you're evaluating P(n, k), you are essentially saying there are n objects and you will need to arrange them in k spaces.

This is essentially the same as: $^{6}P_4$ , which follows the formula:

$P(6, 4) = ^{6}P_4 = \frac{6!}{(6 - 4)!} = \frac{6!}{2!}$
If you're dividing by 4!, you are evaluating P(6, 2)

8 0

3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

riadik2000 [5.3K]

Answer:

x<-3 I HOPE THIS HELPED!!

Step-by-step explanation:

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3 0

3 years ago

Find sin(a+B)

diamong [38]

Answer:

Cos A=5/13

we have

Cos² A= $1-Sin ²A$

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A= $\sqrt{144/169}=12/13$

again

Tan B=4/3

P/b=4/3

p=4

b=3

h= $\sqrt{3²+4²}=5$

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

Sin(A+B):sinAcosB+CosAsinB

now 

substitute value

Sin(A+B):12/13*3/5+5/13*(-4/5)=36/65-4/13

=16/65 is a required answer

6 0

3 years ago