Write an equation in slope-intercept form for the line with slope -3/4 and y intercept -3

1 answer:

7 0

Slope intercept form is simply
$y = mx + b$

where y and x are the things we see on the graph
m is the slope
and b is the y-intercept

the y-intercept is just what y is equal to when x is 0, so right at the middle of the graph.

so just go ahead and if in!

$y = - \frac{3}{4} x - 3$

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Someone help me with this geometry homework !!!!!! 10 points!

Reil [10]

Answer: 3a = (0, 1) 3b = (2, 1) 3c = (2.5, 1) 3d = (1.6, 1)

4a = (2, 3.5) 4b = (2, 3) 4c = (2, 5.375)

Step-by-step explanation:

The length of AB is 6 and is horizontal (affects the x-coordinate)

$3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)$

$3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)$

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The length of AB is 5 and is vertical (affects the y-coordinate)

$4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)$