Four less than the product of 7 and a number is equal to 8 Use the variable b for unknown number

The curb weight of a new car is 3,347 pounds. How much does the car weigh?

frozen [14]

Answer:

A

Step-by-step explanation:

i think

4 0

3 years ago

Graph the function. Describe its position relative to the graph of the indicated function

sweet [91]

Answer:

C

Step-by-step explanation:

If the parent function is function $y=f(x)$ and $a>0,$ then

the graph of the function $y=f(x-a)$ is translated a units to the right graph of the parent function;
the graph of the function $y=f(x+a)$ is translated a units to the left graph of the parent function;
the graph of the function $y=f(x)+a$ is translated a units up graph of the parent function;
the graph of the function $y=f(x)-a$ is translated a units down graph of the parent function.

In your case, the grapgh of the function $y=2^x+2$ is translated 2 units up the graph of the function $y=2^x.$

6 0

3 years ago

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I WILL MAKE YOU THE BRAINLIEST EASY QUESTION Show the formula for finding the area of a parallelogram. Then find the area of the

Fiesta28 [93]

Answer:

A = bh thus: A=671.34 mm²

Step-by-step explanation:

Area =b* (base) h (Height)

4 0

3 years ago

Read 2 more answers

Solve for x, y = 2(x − 17)^2

Archy [21]

X=17+(sqrt(2y)/2),x=17-(sqrt(2y)/2) i believe is the answer

7 0

2 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago