Answer:
f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Step-by-step explanation:
f' of tan(x) = sec²(x)
f' of csc(x) = -csc(x)cot(x)
General Power Rule: uⁿ = xuⁿ⁻¹ · u'
Step 1: Write equation
2tan³(x) + 5csc⁴(x)
Step 2: Rewrite
2(tan(x))³ + 5(csc(x))⁴
Step 3: Find derivative
d/dx 2(tan(x))³ + 5(csc(x))⁴
- General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
- Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
- Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
- Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Answer:
Median is 83
Range: 61
Step-by-step explanation:
The median is the number in the middle. The range is the max. number subtracted from the min number.
Answer:
9.23
14.43-5.2=9.23
Step-by-step explanation:
Mark me brainliest plZZZZZZZZZZZZZZZZZZZZZZZZZ
The answer is 11 The answer is 11 The answer is 11
Solution
f(r) = 3.14
Now we have to find the area of the circle when the radius (r) = 4.
Plug in r = 4 in f(r) to get the area of the circle.
f(4) = 3.14
f(4) = 3.14 * 4 * 4
f(4) = 3.14 *16
f(4) = 50.24
The answer is C. 50.24