Answer:
Take another look at 4 and 6.
The others are correct.
Step-by-step explanation:
The sides of a 30°-60°-90° right triangle have the ratio 1 : √3 : 2. All your triangles (should) have these ratios.
Answer:
a₁₃ = - 27x - 41
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 3x + 7
d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)
= - 5x + 3 + 3x - 7
= - 2x - 4
Then
a₁₃ = - 3x + 7 + 12(- 2x - 4)
= - 3x + 7 - 24x - 48
= - 27x - 41
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
Answer: it is p
Step-by-step explanation:
Answer:
11 coins for $1.99
Step-by-step explanation:
The maximum total less than $2 is $1.99. It takes 11 coins to make that total. It would take 1 fewer if the nickel were not required.
Starting with the minimum required coins, which total $0.91, we need to add $1.08 using a minimum number of coins. To minimize the added coins, we start with the largest we can use without going over the total: 2×50¢ + 1×5¢ + 3×1¢. These 6 coins added to the required 5 coins give the desired total using 11 coins.
11 coins: $1.99 . . . . (3×50¢ +1×25¢ +1×10¢ +2×5¢ +4×1¢)
$1.99 is the highest possible total less than $2.00, and it takes a minimum of 11 coins to make that total.