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Oksanka [162]
3 years ago
9

20. Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal

point (1, –6)?
x(t) = –5 + t; y(t) = 3 – 6t
x(t) = –5 + 3t; y(t) = 1 – 6t
x(t) = –5 + 6t; y(t) = 3 – 9t
x(t) = –5 + 8t; y(t) = 1 – 7t
Mathematics
1 answer:
lesya [120]3 years ago
7 0

Given:

Initial point = (–5, 3)

Terminal point = (1, –6)

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1.

Solution:

The interval is 0 ≤ t ≤ 1, initial point is (–5, 3) and terminal point is (1, –6). It means,

x(0)=-5,y(0)=3

x(1)=1,y(1)=-6

Put t=1 in each parametric equation.

In option A,

x(1)=-5+1=-4\neq 1

In option B,

x(1)=-5+3(1)=-5+3=-2\neq 1

In option D,

x(1)=-5+8(1)=-5+8=3\neq 1

Therefore, options A, B and D are incorrect.

In option C,

x(1)=-5+6(1)=-5+6=1

y(1)=3-9(1)=3-9=-6

Put t=0 in x(t) and y(t).

x(0)=-5+6(0)=-5

y(0)=3-9(0)=3

Since, only in option C x(0)=-5,y(0)=3,x(1)=1,y(1)=-6, therefore, the correct option is C.

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Answer:

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Given:

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