Come someone please help me and explain this

Max makes $3000 a month. He puts 15% in savings each month. After a year how much would he have in savings?

cricket20 [7]

The answer would be 5,400 ( 3000 times 0.15 would be 450 then, 450 times 12 is 5,400.)

8 0

3 years ago

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5. What is the equation in slope-intercept form for the graph of the line shown?

zhuklara [117]

Answer:

$5. \: y = - 2x - 1 \\ 6. \: y - 4 = 3(x + 2) \\ 7. \: the \: cost \: to \: rent \: the \: game \: center$

3 0

3 years ago

1/3 + 1/4 + 1/6<br> PLEASE SHOW WORK, thank you

Dovator [93]

Answer:

3/4

Step-by-step explanation:

1/3 + 1/4 + 1/6

notice that the denominators consists of the numbers 3, 4 and 6 and that the lowest common multiple for all 3 numbers is 12, hence all these fractions can be expressed with a denominator of 12

i.e

1/3 = 4/12

1/4 = 3/12

1/6 = 2/12

hence,

1/3 + 1/4 + 1/6

= 4/12 + 3/12 + 2/12

= (4+3+2) / 12

= 9/12 (simply)

= 3/4

3 0

3 years ago

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A phone company offers two monthly plans. Plan A costs $11 plus an additional $0.11 for each minute of calls. Plan B costs $27 p

irina1246 [14]

Solution:

Let x represent a number of calling minutes. According to the problem, we want:

$11\text{ + 0.11 x = }27\text{ + 0.07 x}$

now, putting the similar terms together, we obtain:

$0.11\text{ x - 0.07 x = 27 -11 }$

this is equivalent to:

$0.04x\text{ = 16}$

now, solving for x, we get:

$x\text{ = }\frac{16}{0.04}\text{ = 400}$

then, the correct answer for the first question is:

400 minutes is the number of minutes the two plans cost the same

now, for the second question, we can replace the above value (400 minutes) into the following equation:

$11\text{ + 0.11(400) = }55$

so that, the correct answer for the second question is:

$55 is the cost when the two plans cost the same

3 0

1 year ago

17

Sauron [17]

let's firstly find the equation of the parabola, bearing in mind that x-intercepts or solutions/zeros/roots means y = 0.

$\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2-9 \\\\\\ \textit{we also know that } \begin{cases} x=0\\ y=-6 \end{cases}\implies -6=a(0-1)^2-9\implies 3=a(-1)^2$

$\bf 3=a\qquad \qquad \textit{therefore}\qquad \qquad \boxed{y=3(x-1)^2-9} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{y}{0}=3(x-1)^2-9\implies 9=3(x-1)^2\implies \cfrac{9}{3}=(x-1)^2\implies 3=(x-1)^2 \\\\\\ \pm\sqrt{3}=x-1\implies \pm\sqrt{3}+1=x\implies x= \begin{cases} \sqrt{3}+1\\ -\sqrt{3}+1 \end{cases}\implies x\approx \begin{cases} 2.73\\ -0.73 \end{cases}$

8 0

3 years ago

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