Determine Mrs chauke'sAnnual income if she earns R32 040 per month
1 answer:
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Remark
This is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.
Question One
In the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid. The graph is the left one for this question.
Question Two
Here I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.
Begin with the slope
Two lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2
Formula
m1 * m2 = - 1
4 * m2 = -1 Divide by 4
m2 = -1/4
So far what you have is
y = (-1/4)x + b
Now use the given point to solve for b
x = 5
y = - 1
b = ??
-1 = (-1/4)*5 + b
-1 = -5/4 + b Add 5/4 to both sides
-1 + 5/4 + b Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4
So the line that you want is
y = (-1/4) x + 1/4
Answers
One: x = - 7
Two: y = (-1/4)x + 1/4
Note
The right graph is of y = 4x - 7 and y = (-1/4)x + 1/4
This is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.
Question One
In the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid. The graph is the left one for this question.
Question Two
Here I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.
Begin with the slope
Two lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2
Formula
m1 * m2 = - 1
4 * m2 = -1 Divide by 4
m2 = -1/4
So far what you have is
y = (-1/4)x + b
Now use the given point to solve for b
x = 5
y = - 1
b = ??
-1 = (-1/4)*5 + b
-1 = -5/4 + b Add 5/4 to both sides
-1 + 5/4 + b Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4
So the line that you want is
y = (-1/4) x + 1/4
Answers
One: x = - 7
Two: y = (-1/4)x + 1/4
Note
The right graph is of y = 4x - 7 and y = (-1/4)x + 1/4
Answer with Step-by-step explanation:
We are given that
A and B are matrix.
A.We know that for two square matrix A and B
Then,
Therefore, it is true.
B. det A is the product of diagonal entries in A.
It is not true for all matrix.It is true for upper triangular matrix.
Hence, it is false.
C.
When is a factor of the characteristics polynomial of A then -5 is an eigenvalue of A not 5.
Hence, it is false.
D.An elementary row operation on A does not change the determinant.
It is true because when an elementary operation applied then the value of matrix A does not change.