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mestny [16]
3 years ago
13

7(2x+6)=1 plzzz Yelp

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Answer:

x = -41/14

Step-by-step explanation:

7(2x+6)=1

Distribute

14x +42 =1

Subtract 42 from each side

14x+42-42 = 1-42

14x = -41

Divide each side by 14

14x/14 = -41/14

x = -41/14

Ierofanga [76]3 years ago
4 0

Answer:

x=-\dfrac{41}{14}

Step-by-step explanation:

7(2x+6)=1

Expand parentheses:

14x+42=1

Subtract 42 from both sides:

14x=-41

Divide both sides by 14:

x=-\dfrac{41}{14}

Hope this helps!

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3 years ago
In ΔTUV, v = 4.9 cm, ∠T=41° and ∠U=59°. Find the length of t, to the nearest 10th of a centimeter.
son4ous [18]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Can you please help me out
aniked [119]

In order to solve this question, we need to find the area of the yellow ring and the total area. The area of the yellow ring is equal to the area of the outer ring minus the area of the red circle, that is

\begin{gathered} A_{\text{yellow}}=\pi4^2-\pi1^2 \\ A_{\text{yellow}}=16\pi-\pi \\ A_{\text{yellow}}=15\pi \\ A_{\text{yellow}}=47.124 \end{gathered}

and the total area is the area of the entire square, that is

\begin{gathered} A_{\text{total}}=10^2 \\ A_{\text{total}}=100 \end{gathered}

Then, the probability that the dart is within the yellow outer ring is given by

\begin{gathered} P(\text{inside yellow ring)=}\frac{A_{yellow}}{A_{total}} \\ P(\text{inside yellow ring)=}\frac{47.124_{}}{100} \end{gathered}

then by rounding the numetaror to the nearest whole number , the answer is

P(\text{inside yellow ring)=}0.47

6 0
1 year ago
What is the converse of the following conditional statement?<br><br> If x = –10, then x2 = 100.
Usimov [2.4K]
The converse is: If x2=100, then x=-10
7 0
4 years ago
Read 2 more answers
The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random
ser-zykov [4K]

Answer:

Probability that both eggs are cracked is 0.0001.

Step-by-step explanation:

We are given that the probability that an egg on a production line is cracked is 0.01.

Two eggs are selected at random  from the production line.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 2 eggs

            r = number of success = both eggs are cracked

            p = probability of success which in our question is probability that

                 an egg on a production line is cracked, i.e; p = 0.01

<u><em>Let X = Number of eggs on a production line that are cracked</em></u>

So, X ~ Binom(n = 2, p = 0.01)

Now, Probability that both eggs are cracked is given by = P(X = 2)

                P(X = 2) =  \binom{2}{2} \times 0.01^{2} \times (1-0.01)^{2-2}

                              =   1\times 0.01^{2} \times 0.99^{0}

                              =  0.0001

<em>Therefore, probability that both eggs are cracked is </em><em>0.0001</em><em>.</em>

6 0
4 years ago
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